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Saturday, March 9, 2019

Ohm’s Law Series-Parallel Circuits Calculation Essay

To end up the discussion of Series-Parallel Circuits, I would like to post this last one remaining topic which is or so Ohms Law of Series-Parallel Circuits for draws and potencys. I did not even mentioned in my prior topics on how to deal with its legitimates and voltages regarding this type of roofy connection.Ohms Law in Series-Parallel CircuitsOhms Law in Series-Parallel Circuits afoot(predicate)The contribute current of the series-parallel circuits depends on the total resistance offered by the circuit when connected crossways the voltage source. The current flow in the entire circuit and it will divide to flow through parallel assortes. In case of parallel branch, the current is reciprocally proportional to the resistance of the branch that is the greater current flows through the least(prenominal) resistance and vice-versa. Then, the current will then sum up over again after flowing in different circuit branch which is the said(prenominal) as the current sour ce or total current.The total circuit current is the same at each end of a series-parallel circuit, and is be to the current flow through the voltage source.Ohms Law in Series-Parallel Circuits VoltageThe voltage drop crossways a series-parallel circuits also slide by the same way as in series and parallel circuits. In series parts of the circuit, the voltage drop depends on the individual value of the resistors. In parallel parts of the circuit, the voltage crossways each branch argon the same and carries a current depends on the individual determine of the resistors.If in case of circuit below, the voltage of the series resistance forming a branch of the parallel circuit will divide the voltage across the parallel circuit. If in case of the single resistance in a parallel branch, the voltage across is the same as the sum of the voltages of the seriesresistances.The sum of the voltage across R3 and R4 is the same as the voltage across R2.Finally, the sum of the voltage drop a cross each paths between the cardinal terminal of the series-parallel circuit is the same as the total voltage utilise to the circuit.Lets have a very simple role model of this calculation for this topic. Considering the circuit below with its given values, lets visualize the total current, current and voltage drop across each resistances.What is the total current, current and voltage across each resistancesHere is the simple calculation of the circuit abovea. image first the total resistance of the circuitThe equivalent resistance for R2 and R3 isR2-3 = 25X50/ 25+50 = 16.67 ohmsR total = 30 ohms + 16.67 ohms = 46.67 ohmsb. Calculate the Total Current using Ohms LawI1 = 120V / 46.67 Ohms = 2.57 Amp. Since R1 is in series connection, the total current is the same for that path.c. Calculating the voltage drop for R1VR1 = 2.57 Amp x 30 ohms = 77.1 voltsd. Calculate the voltage drop across R2 and R3.Since the equivalent resistance for R2 and R3 as metric above is 16.67 ohms, we ca n now calculate the voltage across each branch.VR2 = VR3 = 2.57 Amp x 16.67 ohms = 42. 84 voltse. Finally, we can now calculate the individual current for R2 and R3I2 = VR2 / R2 = 42.84 volts / 25 ohms = 1.71 Amp.I3 = VR3 / R3 = 42.84 volts / 50 ohms = 0.86 Amp.You may also underwrite if the current in each path of the parallel branch are correct by adding its currentsI1 = I2 + I3 = 1.71 Amp + 0.86 Amp = 2.57 Amp. which is the same as calculated above. Therefore, we can say that our answer is correct.

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